What is the completely factored form of f(x)=x3+5x2+4x−6?f(x)=(x−3)(x−(−1+i3√))(x−(−1−i3√))f(x)=(x+3)(x−(−1+i3√))(x−(−1−i3√))f(x)=(x+3)(x−(−1+3√))(x−(−1−3√))f(x)=(x−3)(x−(−1+3√))(x−(−1−3√))
Accepted Solution
A:
[tex]f(x)=x^3+5x^2+4x-6[/tex] [tex]f(-3)=(-3)^3+5(-3)^2+4(-3)-6=0\implies x+3\text{ is a factor of }f(x)[/tex]